4-x^2/4=5x

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Solution for 4-x^2/4=5x equation: 


x in (-oo:+oo)

4-((x^2)/4) = 5*x // - 5*x

4-((x^2)/4)-(5*x) = 0

4-((x^2)/4)-5*x = 0

4-1/4*x^2-5*x = 0

DELTA = (-5)^2-(-1/4*4*4)

DELTA = 29

DELTA > 0

x = (29^(1/2)+5)/(-1/4*2) or x = (5-29^(1/2))/(-1/4*2)

x = -2*(29^(1/2)+5) or x = -2*(5-29^(1/2))

x in { -2*(29^(1/2)+5), -2*(5-29^(1/2)) }

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